![]() Zero value disables the byte-range support completely. By default, the number of ranges is not limited. Requests that exceed the limit are processed as if there were no byte Limits the maximum allowed number of ranges in byte-range requests. This directive appeared in version 1.1.2. ![]() This in theory it (or anything being forwarded the header as-is) could be vulnerable to excessive resource use on odd requests. Nginx does not employ it: it does fulfil requests for large numbers of separate ranges by default, only subject to header size limits. The ancient check is not specific to apache2, it is only specific to one particular approach of mitigating such DoS surface on apache2. My question is, how do I find the program thats vulnerable, and how do I then close the vulnerability on the server? I am trying to close this vulnerability on the server, however, I do NOT have apache installed on the server, So I don't know why this vulnerability is showing up! On the Ubuntu Server, the output of ss -lnpt is: State Recv-Q Send-Q Local Address:Port Peer Address:Port Process | The Apache web server is vulnerable to a denial of service attack when numerous ![]() Which is an alias command for nmap -script=vulnĪfter issuing the command with my server's IP address, nmap reported the following: | http-vuln-cve2011-3192: To do some vulnerability tests on my Ubuntu Server from my MacOS client machine, I issued the command: nmap_check_for_vulns my.server.ip.address On MacOS, I am using Oh My Zsh! with the nmap plugin enabled. I am also doing some nmap vulnerability tests form my MacOS Client machine. I am running an Ubuntu 20.04 LEMP (Linux, Nginx, MariaDb, PHP) webserver. ![]()
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